Class 7 Maths Formulas
📘 Class 7 Maths
Algebra & Geometry — Formulas, Examples and Solutions
🟦 Part A: Algebra
1. Like Terms
Rule: Terms having the same variables with the same powers are called like terms.
3x + 5x = 8x
Example: 3x + 5x
Solution: 3x + 5x = 8x
Solution: 3x + 5x = 8x
Answer: 8x
2. Addition of Algebraic Expressions
Rule: Add the coefficients of like terms.
4x + 7 + 3x + 5
Solution:
4x + 3x + 7 + 5
= 7x + 12
4x + 3x + 7 + 5
= 7x + 12
Answer: 7x + 12
3. Subtraction of Algebraic Expressions
(8x + 7) - (3x + 2)
Solution:
= 8x + 7 - 3x - 2
= 5x + 5
= 8x + 7 - 3x - 2
= 5x + 5
Answer: 5x + 5
4. Multiplication of a Monomial
a(b + c) = ab + ac
Example: 3(x + 4)
Solution:
3(x + 4) = 3x + 12
Solution:
3(x + 4) = 3x + 12
Answer: 3x + 12
5. Multiplication of Two Monomials
ax × by = abxy
Example: 3x × 4y
Solution:
3x × 4y = 12xy
Solution:
3x × 4y = 12xy
Answer: 12xy
6. Simple Linear Equation
Rule: Whatever operation is performed on one side must also be performed on the other side.
x + 7 = 15
Solution:
x = 15 − 7
x = 8
x = 15 − 7
x = 8
Answer: x = 8
7. Equation with Multiplication
3x = 21
Solution:
x = 21 ÷ 3
x = 7
x = 21 ÷ 3
x = 7
Answer: x = 7
8. Equation with Division
x ÷ 5 = 6
Solution:
x = 6 × 5
x = 30
x = 6 × 5
x = 30
Answer: x = 30
🟩 Part B: Geometry
1. Complementary Angles
A + B = 90°
Example: One angle is 35°.
Solution:
90° − 35° = 55°
Solution:
90° − 35° = 55°
Answer: 55°
2. Supplementary Angles
A + B = 180°
Example: One angle is 120°.
Solution:
180° − 120° = 60°
Solution:
180° − 120° = 60°
Answer: 60°
3. Linear Pair
A + B = 180°
Example: One angle is 75°.
Solution:
180° − 75° = 105°
Solution:
180° − 75° = 105°
Answer: 105°
4. Vertically Opposite Angles
Vertically opposite angles are equal.
Example: If one angle is 65°, find its vertically opposite angle.
Solution: The vertically opposite angle is also 65°.
Solution: The vertically opposite angle is also 65°.
Answer: 65°
5. Sum of Angles of a Triangle
A + B + C = 180°
Example: Two angles are 50° and 60°.
Solution:
50° + 60° + C = 180°
C = 180° − 110°
C = 70°
Solution:
50° + 60° + C = 180°
C = 180° − 110°
C = 70°
Answer: C = 70°
6. Exterior Angle of a Triangle
Exterior angle = Sum of the two opposite interior angles
Example: Opposite interior angles are 50° and 70°.
Solution:
50° + 70° = 120°
Solution:
50° + 70° = 120°
Answer: 120°
7. Perimeter of a Rectangle
P = 2(l + b)
Example: Length = 8 cm, Breadth = 5 cm.
Solution:
P = 2(8 + 5)
= 2 × 13
= 26 cm
Solution:
P = 2(8 + 5)
= 2 × 13
= 26 cm
Answer: 26 cm
8. Area of a Rectangle
A = l × b
Example: Length = 10 cm, Breadth = 6 cm.
Solution:
A = 10 × 6
= 60 cm²
Solution:
A = 10 × 6
= 60 cm²
Answer: 60 cm²
9. Perimeter of a Square
P = 4 × side
Example: Side = 7 cm.
Solution:
P = 4 × 7
= 28 cm
Solution:
P = 4 × 7
= 28 cm
Answer: 28 cm
10. Area of a Square
A = side²
Example: Side = 9 cm.
Solution:
A = 9²
= 81 cm²
Solution:
A = 9²
= 81 cm²
Answer: 81 cm²
11. Area of a Triangle
A = ½ × base × height
Example: Base = 12 cm, Height = 5 cm.
Solution:
A = ½ × 12 × 5
= 6 × 5
= 30 cm²
Solution:
A = ½ × 12 × 5
= 6 × 5
= 30 cm²
Answer: 30 cm²
12. Area of a Parallelogram
A = base × height
Example: Base = 10 cm, Height = 6 cm.
Solution:
A = 10 × 6
= 60 cm²
Solution:
A = 10 × 6
= 60 cm²
Answer: 60 cm²
13. Circumference of a Circle
C = 2πr
Example: Radius = 7 cm. Take π = 22/7.
Solution:
C = 2 × 22/7 × 7
= 44 cm
Solution:
C = 2 × 22/7 × 7
= 44 cm
Answer: 44 cm
14. Area of a Circle
A = πr²
Example: Radius = 7 cm. Take π = 22/7.
Solution:
A = 22/7 × 7 × 7
= 154 cm²
Solution:
A = 22/7 × 7 × 7
= 154 cm²
Answer: 154 cm²
⭐ Quick Revision Table
| Topic | Formula / Rule |
|---|---|
| Complementary Angles | A + B = 90° |
| Supplementary Angles | A + B = 180° |
| Linear Pair | A + B = 180° |
| Vertically Opposite Angles | They are equal |
| Triangle Angles | A + B + C = 180° |
| Rectangle Perimeter | 2(l + b) |
| Rectangle Area | l × b |
| Square Perimeter | 4s |
| Square Area | s² |
| Triangle Area | ½ × b × h |
| Parallelogram Area | b × h |
| Circle Circumference | 2πr |
| Circle Area | πr² |
| Distributive Property | a(b + c) = ab + ac |
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